Find Second Largest Duplicate Elements in an Array in Java with dry rub example:, A Step-by-Step Walkthrough with Sample Code with Dry Run

Find Second Largest Duplicate Elements in an Array in Java with dry rub example:, A Step-by-Step Walkthrough with Sample Code with Dry Run Working with arrays is a common task in programming, and one of the challenges that you may encounter is finding duplicate elements in an array. In this article, we will discuss how to use nested for loops to find and print duplicate elements in an array in Java. To begin, let's define an array of integers that we will use for our examplesWorking with arrays is a common task in programming, and one of the challenges that you may encounter is finding duplicate elements in an array. In this article, we will discuss how to use nested for loops to find and print duplicate elements in an array in Java. To begin, let's define an array of integers that we will use for our examples

 
  int array[] = {1, 6, 2, 3, 4, 6, 7, 8, 10, 7, 9, 6};

Now that we have our array defined, we can start writing the code that will find and print any duplicate elements that it contains. The first thing we need to do is set up two for loops: an outer loop and an inner loop. The outer loop will iterate over every element in the array, and the inner loop will iterate over every element in the array that comes after the element that the outer loop is currently on. This will allow us to compare every element in the array to every other element in the array.

 
    for (int i = 0; i < array.length - 1; i++) {
    for (int j = i + 1; j < array.length; j++) {
        // code to check for duplicates goes here
     }
    }

Next, we need to write the code that will check for duplicates. This is where the inner loop comes in. Inside the inner loop, we can use an if statement to check if the element that the outer loop is currently on is equal to the element that the inner loop is currently on. If they are equal, then we have found a duplicate element and we can print it.

 
     if (array[i] == array[j]) {
      System.out.print(array[j] + " ");
    }
 

At this point, our code will find and print any duplicate elements in the array, but it will not stop once it finds the first duplicate. This is where the flag variable comes in. We can use a flag variable to keep track of whether a duplicate has been found or not, and then use an if statement at the end of the outer loop to break out of both loops if the flag variable is set to 1.

 
 
    int flag = 0;
     for (int i = 0; i < array.length - 1; i++) {
     for (int j = i + 1; j < array.length; j++) {
        if (array[i] == array[j]) {
            System.out.print(array[j] + " ");
            flag = 1;
            break;
        }
      }
 
      if (flag == 1) {
        break;
      }
     }
     int flag = 0;
     for (int i = 0; i < array.length - 1; i++) {
      for (int j = i + 1; j < array.length; j++) {
        if (array[i] == array[j]) {
            System.out.print(array[j] + " ");
            flag = 1;
            break;
        }
      }
 
      if (flag == 1) {
        break;
     }
   }

Now, when the code finds a duplicate element, it will print the element, set the flag variable to 1, and then break out of both loops. This means that the code will only print the first duplicate element that it finds and then stop. Here is the complete code that we have written so far:

 
     public class Main {
     public static void main(String[] args) {
        int array[] = {1, 6, 2, 3, 4, 6, 7, 8, 10, 7, 9, 6};
 
        int flag = 0;
        for (int i = 0; i < array.length - 1; i++) {
            for (int j = i + 1; j < array.length; j++) {
                if (array[i] == array[j]) {
                    System.out.print(array[j] + " ");
                    flag = 1;
                    break;
                }
            }
 
            if (flag == 1) {
                break;
            }
          }
         }
        }
 

let's Dry Rub it, Here is More details The program defines an array of integers and then uses nested for loops to check if any of the elements in the array are duplicates. If a duplicate is found, the program prints the duplicate element and then breaks out of both loops. The code uses a flag variable to keep track of whether a duplicate has been found or not. Here is an example of how the code might run with some sample input:

 
     int array[] = {1, 6, 2, 3, 4, 6, 7, 8, 10, 7, 9, 6};
 
     int flag = 0;
     for (int i = 0; i < array.length - 1; i++) {
     for (int j = i + 1; j < array.length; j++) {
        if (array[i] == array[j]) {
            System.out.print(array[j] + " ");
            flag = 1;
            break;
         }
      }
 
      if (flag == 1) {
        break;
     }
   }
 

In this example, the first time the inner loop runs, array[i] is 1 and array[j] is 6. Since 1 is not equal to 6, the program continues to the next iteration of the inner loop. The second time the inner loop runs, array[i] is still 1 and array[j] is now 2. Again, 1 is not equal to 2, so the program continues to the next iteration of the inner loop. This process continues until array[i] is 1 and array[j] is 6 again, at which point the if statement evaluates to true and the program prints 6 and sets the flag variable to 1. Since the flag variable is now 1, the if statement at the end of the outer loop evaluates to true and the program breaks out of both loops. This means that the program only prints the first duplicate element that it finds and then stops.